Question 1: Given a list of employees, you need to filter all the employee whose age is greater than 20 and print the employee names.(Java 8 APIs only)

 Answer:
You can simply do it using the below statement.

List<String> employeeFilteredList = employeeList.stream()
                  .filter(e->e.getAge()>20)
                  .map(Employee::getName)
                  .collect(Collectors.toList());

------------------------------------------------------------------------------------------------------------------------

import java.util.ArrayList;
import java.util.List;
import java.util.stream.Collectors;
 
public class MaximumUsingStreamMain {
    public static void main(String args[])
    {
        List<Employee> employeeList = createEmployeeList();
        List<String> employeeFilteredList = employeeList.stream()
                  .filter(e->e.getAge()>20)
                  .map(Employee::getName)
                  .collect(Collectors.toList());
 
        employeeFilteredList.forEach((name)-> System.out.println(name));
 
    }
 
    public static List<Employee> createEmployeeList()
    {
        List<Employee> employeeList=new ArrayList<>();
 
        Employee e1=new Employee("John",21);
        Employee e2=new Employee("Martin",19);
        Employee e3=new Employee("Mary",31);
        Employee e4=new Employee("Stephan",18);
        Employee e5=new Employee("Gary",26);
 
        employeeList.add(e1);
        employeeList.add(e2);
        employeeList.add(e3);
        employeeList.add(e4);
        employeeList.add(e5);
 
        return employeeList;
    }
}

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